2j^2+4j-126=0

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Solution for 2j^2+4j-126=0 equation:


Simplifying
2j2 + 4j + -126 = 0

Reorder the terms:
-126 + 4j + 2j2 = 0

Solving
-126 + 4j + 2j2 = 0

Solving for variable 'j'.

Factor out the Greatest Common Factor (GCF), '2'.
2(-63 + 2j + j2) = 0

Factor a trinomial.
2((-9 + -1j)(7 + -1j)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-9 + -1j)' equal to zero and attempt to solve: Simplifying -9 + -1j = 0 Solving -9 + -1j = 0 Move all terms containing j to the left, all other terms to the right. Add '9' to each side of the equation. -9 + 9 + -1j = 0 + 9 Combine like terms: -9 + 9 = 0 0 + -1j = 0 + 9 -1j = 0 + 9 Combine like terms: 0 + 9 = 9 -1j = 9 Divide each side by '-1'. j = -9 Simplifying j = -9

Subproblem 2

Set the factor '(7 + -1j)' equal to zero and attempt to solve: Simplifying 7 + -1j = 0 Solving 7 + -1j = 0 Move all terms containing j to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1j = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1j = 0 + -7 -1j = 0 + -7 Combine like terms: 0 + -7 = -7 -1j = -7 Divide each side by '-1'. j = 7 Simplifying j = 7

Solution

j = {-9, 7}

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